result = eval("(3+5)*7")
# 56

result2 = sorted([('홍길동', 35), ('이순신', 75), ('아무개', 50)], key = lambda x: x[1], reverse = True)
# [('이순신', 75), ('아무개', 50), ('홍길동', 35)]

from itertools import permutations, combinations, product

data = ['A', 'B', 'C']
result1 = list(permutations(data, 3)) # 순열 구하기
result2 = list(combinations(data, 2)) # 조합 구하기
result3 = list(product(data, repeat=2)) # 순열 구하기 (중복 허용)

import heapq

h = []
heapq.heappush(h, value) # 원소 삽입
heapq.heappop(h) # 원소 꺼내기

from bisect import bisect_left, bisect_right

a = [1, 2, 4, 4, 8]
x = 4
print(bisect_left(a, x)) # 2
print(bisect_right(a, x)) # 4

from collections import deque, Counter

data = deque([2, 3, 4])
data.appendleft(1)
data.append(5)
print(list(data)) # [1, 2, 3, 4, 5]

counter = Counter(['red', 'blue', 'red', 'green', 'blue', 'blue'])
print(counter['blue']) # 3
print(dict(counter)) # {'red': 2. 'blue': 3, 'green': 1}

import math

print(math.factorial(5)) # 5! => 120
print(math.gcd(21, 14)) # 7